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(A) Solvolysis proceeds via the formation of a carbocation intermediate. The stability of the carbocation determines the rate of reaction.In all three

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$II > I > III$

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(A) Solvolysis proceeds via the formation of a carbocation intermediate. The stability of the carbocation determines the rate of reaction.In all three cases,a tertiary benzylic carbocation is formed upon the loss of the chloride ion.Compound $II$ has an additional electron-donating methyl group $(-CH_3)$ at the ortho position relative to the carbocation center,which stabilizes the carbocation through the inductive effect.Compound $I$ has a cyclopropyl group at the para position. The cyclopropyl group is electron-donating due to $\sigma$-bond resonance (bent bonds),which stabilizes the carbocation.Compound $III$ is a simple tertiary benzylic carbocation without any additional electron-donating groups on the ring.Comparing the stabilization: The methyl group in $II$ provides significant inductive stabilization. The cyclopropyl group in $I$ also provides stabilization,but the inductive effect of the methyl group in $II$ is more effective in this specific benzylic system.Thus,the order of stability of the carbocations,and hence the rate of solvolysis,is $II > I > III$.

The decreasing order of reactivity of the compounds given below towards solvolysis under identical conditions is:

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